Trigonometric Functions & Graphs

🔢 Maths Years 10–11 Higher

Degrees and radians, the unit circle definition of sine and cosine, the graphs of sin(x), cos(x) and tan(x), and finding multiple solutions to trig equations.

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In g7 SOHCAHTOA you used sine, cosine and tangent to solve right-angled triangles, and in g15 Sine & Cosine Rules you extended them to any triangle — but both of those only ever used angles between 0° and 180°. Set sine or cosine free from a triangle altogether and something new appears: a smooth, endlessly repeating wave. This chapter is about that wave — the graphs of sin(x), cos(x) and tan(x), and what they tell you about angles you can't just look up in a triangle.

Why this matters: repeating (periodic) motion — a Ferris wheel, a sound wave, the tide, alternating current — is modelled with sine and cosine graphs, and the AC electricity in your walls literally follows a sine wave 50 times a second. On the Extended paper, "solve sin x = k for 0° ≤ x ≤ 360°" questions catch out students who find one solution and stop — the graph's symmetry always hides a second one.

1. Degrees and radians

Angles can be measured in degrees (a full turn = 360°) or in radians (a full turn = 2π radians). Radians measure an angle by the length of arc it cuts out on a unit circle, which is why calculus and physics almost always use them. To convert: multiply degrees by π/180 to get radians, or multiply radians by 180/π to get degrees.

DegreesRadians
360°2π
180°π
90°π/2
60°π/3
45°π/4
30°π/6

2. The unit circle: sine and cosine beyond the triangle

Picture a point going anticlockwise around a circle of radius 1, centred on the origin, starting on the positive x-axis. As the point turns through angle x, its y-coordinate is defined to be sin(x) and its x-coordinate is defined to be cos(x). For 0° to 90° this matches SOHCAHTOA exactly (opposite/hypotenuse and adjacent/hypotenuse on a radius-1 triangle) — but the unit circle keeps working past 90°, giving sine and cosine values for any angle, including negative angles and angles over 360°.

3. The graphs of sin(x), cos(x) and tan(x)

1−100°90°180°270°360°amplitude = 1period = 360°
y = sin(x): amplitude 1 (centre line to peak), period 360° (one full repeat), peak at 90°, trough at 270°.

4. Solving a trig equation: reading multiple solutions off the graph

Because the sine curve is symmetric, an equation like sin(x) = 0.5 almost always has more than one solution in a given range. Your calculator (inverse sine) only ever gives you the principal value — the first one. To find the rest, use the graph's symmetry:

Worked example. Solve sin(x) = 0.5 for 0° ≤ x ≤ 360°.
Calculator: sin-1(0.5) = 30°. This is the principal value.
Sine is also positive in the second "hump" of the graph (90° to 180°), symmetric about x = 90°, giving a second solution of 180° − 30° = 150°.
Check on the graph: at x = 30° and x = 150°, the curve crosses the horizontal line y = 0.5 at exactly two points between 0° and 360° — sine is negative for the rest of the range, so there are no more.
x = 30° or x = 150°.
Worked example (cosine). Solve cos(x) = 0.6 for 0° ≤ x ≤ 360°.
Calculator: cos-1(0.6) = 53.1° (principal value).
Cosine is symmetric about x = 180°, so the second solution is 360° − 53.1° = 306.9°.
x = 53.1° or x = 306.9° (1 d.p.).
Common exam mistake: giving only the calculator's single answer and stopping. Whenever a range wider than the "obvious" triangle angle is given (like 0° to 360°), sketch or picture the graph and use its symmetry to check for a second (or sometimes third or fourth) solution — losing that second answer is the single most common way marks are dropped on this topic.

Exam technique: always sketch a quick, rough sine or cosine curve first and mark the target y-value as a horizontal line across it. Wherever that line crosses the curve within the given range is a valid solution — count the crossings before you start calculating so you know how many answers to expect.

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