Introduction to Differentiation

🔢 Maths Year 11 Higher

Differentiate polynomials, find the gradient at a point, a tangent equation, and stationary points.

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The gradient of a straight line is the same everywhere, but a curve keeps bending, so its steepness changes from point to point. Differentiation is the machine that gives a formula — written dy/dx — for the gradient at any point on a curve. It is the gateway to calculus and one of the most powerful tools in the whole syllabus.

Why this matters: gradients describe rates of change — speed, growth, profit. Finding where a curve turns tells engineers a maximum load or a designer a minimum cost. On the Extended paper differentiation is a guaranteed topic, usually a tangent or a turning-point question worth several marks.

1. The rule for powers of x

For a term axn, the derivative is anxn−1: multiply by the power, then knock the power down by one. Differentiate each term separately; a constant on its own differentiates to 0.

Term ydy/dxReason
x³3x²bring down 3, power → 2
5x²10x5 × 2 = 10, power → 1
4x44x¹ → 4x⁰ = 4
70a constant has no gradient
Worked: y = 2x³ − 5x² + 4x − 9. Differentiate term by term: dy/dx = 6x² − 10x + 4. (The −9 vanishes.)

2. Gradient at a point, and the tangent

gradient here = dy/dxy = curve
The tangent's slope at a point is the value of dy/dx there.
Worked tangent: y = x² − 3x + 2 at x = 4. dy/dx = 2x − 3, so at x = 4 the gradient m = 2(4) − 3 = 5. The point: y = 16 − 12 + 2 = 6, so (4, 6). Tangent: y − 6 = 5(x − 4) → y = 5x − 14.

3. Stationary (turning) points: dy/dx = 0

At a peak or a valley the curve is momentarily flat, so its gradient is zero. Solve dy/dx = 0 to find the x-coordinate(s), then substitute back for y. To classify:

maxmingradient = 0 at each turning point
At every turning point the tangent is horizontal, so dy/dx = 0.
Worked: y = x² − 6x + 5. dy/dx = 2x − 6. Set to 0: 2x − 6 = 0 → x = 3. Then y = 9 − 18 + 5 = −4, so the turning point is (3, −4). Since d²y/dx² = 2 > 0, it is a minimum.
Common exam mistake: differentiating the constant term wrong (7 becomes 0, not 7) and forgetting to substitute back for the y-coordinate of a turning point. "Find the coordinates" needs both x and y.

Exam technique: the command word Find the equation of the tangent expects three shown steps — differentiate, evaluate the gradient, use y − y₁ = m(x − x₁). Each is a mark.

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